user_can()
云策文档标注
概述
user_can() 函数用于检查特定用户是否拥有指定的权限。它支持元权限（如 edit_post）的检查，并可传递额外参数（如对象ID）进行更精确的验证。
关键要点
- 函数返回布尔值，表示用户是否具备给定权限
- 支持用户ID或WP_User对象作为第一个参数
- 可处理元权限，通过map_meta_cap()映射到原始权限
- 可选参数$args用于传递对象ID等额外信息
代码示例
user_can( $user->ID, 'edit_posts' );
user_can( $user->ID, 'edit_post', $post->ID );
user_can( $user->ID, 'edit_post_meta', $post->ID, $meta_key );注意事项
- 若用户未登录，函数会创建匿名用户对象进行处理
- 从WordPress 5.3.0版本起，正式支持可变参数...$args
- 相关函数包括current_user_can()和map_meta_cap()
原文内容
Returns whether a particular user has the specified capability.
Description
This function also accepts an ID of an object to check against if the capability is a meta capability. Meta capabilities such as edit_post and edit_user are capabilities used by the map_meta_cap() function to map to primitive capabilities that a user or role has, such as edit_posts and edit_others_posts.
Example usage:
user_can( $user->ID, 'edit_posts' );
user_can( $user->ID, 'edit_post', $post->ID );
user_can( $user->ID, 'edit_post_meta', $post->ID, $meta_key );Parameters
$userint|WP_Userrequired-
User ID or object.
$capabilitystringrequired-
Capability name.
$argsmixedoptional-
Optional further parameters, typically starting with an object ID.
Source
function user_can( $user, $capability, ...$args ) {
if ( ! is_object( $user ) ) {
$user = get_userdata( $user );
}
if ( empty( $user ) ) {
// User is logged out, create anonymous user object.
$user = new WP_User( 0 );
$user->init( new stdClass() );
}
return $user->has_cap( $capability, ...$args );
}